Counting TINYINT values in MySQL

Question

The table structure is like this:

actions: int(10)
unlock: tinyint(1)
user_id: int(20)
name: varchar(50)

I have such query:

SELECT SUM(actions) AS "sum_actions", SUM(unlock) AS "sum_unlock", user_id, name 
 FROM mytable AS `Results` WHERE user_id != 0 GROUP BY user_id 
 ORDER BY sum_actions DESC LIMIT 0,300

This gives #1064 - You have an error in your SQL syntax error.

When I remove SUM(unlock) AS "sum_unlock" then query works. So I thought that it is not possible to summing TINYINTs. So I changed to COUNT(unlock) as "count_unlock" but this didn't help. I don't want to change "unlock" table to INT because it only has boolean values. How can I count the unlock table with summing for each user_id ?

Answer 1

unlock is a reserved word. Try this:

SELECT SUM(actions) AS "sum_actions", SUM(`unlock`) AS "sum_unlock", user_id, name 
FROM mytable AS `Results`
WHERE user_id != 0
GROUP BY user_id 
ORDER BY sum_actions DESC
LIMIT 0,300

Here is a list of reserved words.

Answer 2

You can try SUM(CAST(unlock AS INT)) to count as if the column was an INT column without actually changing it to be an INT column:

SELECT
    SUM(actions) AS "sum_actions",
    SUM(CAST(unlock AS INT)) AS "sum_unlock",
    user_id,
    name 
FROM
    mytable AS `Results`
WHERE
    user_id != 0
GROUP BY
    user_id,
    name
ORDER BY
    sum_actions DESC
LIMIT 0,300