Question

so far I have gotten this far:

prompt$ find path/to/project -type f | grep -v '*.ori|*.pte|*.uh|*.mna' | xargs dos2unix 2> log.txt

However, the files with extensions .ori, .pte, .uh and .mna still show up.

Était-ce utile?

La solution

It is better to leave the excluding to find, see Birei's answer.

The problem with your grep pattern is that you have specified it as a shell glob. By default grep expects basic regular expressions (BRE) as its first argument. So if you replace your grep pattern with: .*\.\(ori\|pte\|uh\|mna\)$ it should work. Or if you would rather use extended regular expressions (ERE), you can enable them with -E. Then you can express the same exclusion like this: .*\.(ori|pte|uh|mna)$.

Full command-line:

find . -type f | grep -vE '.*\.(ori|pte|uh|mna)$'

Autres conseils

One way:

find path/to/project *.* -type f ! \( -name '*.ori' -o -name '*.pte' -o -name '*.uh' -o -name '*.mna' \) 
  | xargs dos2unix 2> log.txt
Licencié sous: CC-BY-SA avec attribution
Non affilié à StackOverflow
scroll top