You can cut the tuple in half:
scheme, netloc, path = parsed_url[:3]
Or, to make it explicit that there are six values and you're ignoring three of them, you could assign to a dummy variable named _
:
scheme, netloc, path, _, _, _ = parsed_url
Domanda
Say I have the following code:
from urlparse import urlparse
parsed_url = urlparse(url)
scheme, netloc, path = parsed_url[0], parsed_url[1], parsed_url[2]
Is there a more elegant or short way of assigning those three variables? It looks a bit messy to write parsed_url
three times (I am expecting something other than renaming parsed_url
to something shorter).
Soluzione
You can cut the tuple in half:
scheme, netloc, path = parsed_url[:3]
Or, to make it explicit that there are six values and you're ignoring three of them, you could assign to a dummy variable named _
:
scheme, netloc, path, _, _, _ = parsed_url
Altri suggerimenti
parsed_url[:3]
will create a subtuple consisting of exactly the wanted parts.
So
scheme, netloc, path = parsed_url[:3]
will do what you need.