Come si usa COUNT (*) in un comunicato in cui?
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27-10-2019 - |
Domanda
Non capisco perché questo non funziona e come risolvere il problema, ho provato varie cose come scrivere
select COUNT(p.OwnerUserId)
, ma che non funziona e non capisco i msg di errore. Non faccio uso di MS SQL (io uso SQLite e MySQL).
Come faccio a scrivere questa query in modo che io possa filtrare il controllo di qualità da 10 o 50? (Dove QC> 50 E ...)
In sostanza collegare lo SQL di seguito in questo URL, eseguirlo e vedrete 1 del nei risultati. http://data.stackexchange.com/stackoverflow/query/new
SELECT
TOP 100
p.OwnerUserId AS [User Link],
sum(ViewCount) as VC,
avg(ViewCount) as AVC,
COUNT(p.OwnerUserId ) as QC
FROM Posts p
join Users on p.OwnerUserId = Users.Id
where PostTypeId = 1 and ViewCount<10000 and CommunityOwnedDate is null
group by p.OwnerUserId
order by AVC desc
Soluzione
SELECT
TOP 100
p.OwnerUserId AS [User Link],
sum(ViewCount) as VC,
avg(ViewCount) as AVC,
COUNT(p.OwnerUserId ) as QC
FROM Posts p
join Users on p.OwnerUserId = Users.Id
where PostTypeId = 1 and ViewCount<10000 and CommunityOwnedDate is null
group by p.OwnerUserId
HAVING COUNT(p.OwnerUserId ) between 10 and 50 -- <<<<<
order by AVC desc
Un'altra opzione è quella di renderlo un sottoquery
SELECT
TOP 100
FROM (
SELECT
p.OwnerUserId AS [User Link],
sum(ViewCount) as VC,
avg(ViewCount) as AVC,
COUNT(p.OwnerUserId ) as QC
FROM Posts p
join Users on p.OwnerUserId = Users.Id
where PostTypeId = 1 and ViewCount<10000 and CommunityOwnedDate is null
group by p.OwnerUserId
) SQ
WHERE QC >= 50
order by AVC desc
Altri suggerimenti
È necessario utilizzare clausola having per filtrare un campo aggregato
Prova questo:
SELECT
TOP 100
p.OwnerUserId AS [User Link],
sum(ViewCount) as VC,
avg(ViewCount) as AVC,
COUNT(p.OwnerUserId ) as QC
FROM Posts p
join Users on p.OwnerUserId = Users.Id
where PostTypeId = 1 and ViewCount<10000 and CommunityOwnedDate is null
group by p.OwnerUserId
HAVING COUNT(p.OwnerUserId ) > 50
order by AVC desc
Quando si utilizza aggregati, è necessario utilizzare having
invece di where
.