MySql Date range manipulation [closed]

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Table example

ROW-------|---ID---|---FROM_DATE-------|---TO_DATE------|---PRICE---

1---------|---10---|---2014-02-01------|---2014-02-28---|---150.00---

2---------|---22---|---2014-01-10------|---2014-02-09---|---200.00---

3---------|---39---|---2014-02-20------|---2014-03-19---|---120.00---

4---------|---45---|---2014-01-15------|---2014-04-14---|---600.00---

Now, I have to calculate how much money (relatively) each ID has created for February 2014 only.

The first row is easy, all the amount is within February 2014.

In the second row I need to calculate that there are 31 days in January and take 9/31 of the amount.

In the third row is much like the second row, there are 28 days in February, thus 9/28 of the amount.

The forth row is tricky, February doesn't show at all and I know there are 90 days between Jan 15 and Apr 14. therefore I should get 28/90 of the amount.

Wanted result:

ROW-------|---ID---|---MONTH----|---SUM---

1---------|---10---|---02/2014---|---150.00---

2---------|---22---|---02/2014---|---58.06---

3---------|---39---|---02/2014---|---38.57---

4---------|---45---|---02/2014---|---186.66---

Please help me how to do it.

Thanks!!!

Answer 1

This is a bit tricky.

Here is one method to count just the overlapping days in February (or any other time period):

select sum(datediff(least(to_date, date('2014-03-01')), greatest(from_date, '2014-02-01'))) as days
from table t
where to_date >= date('2014-02-01') and from_date < date('2014-03-01');

Answer 2

Try this query:

SELECT ROW,ID,'02/2014' MONTH,
(PRICE * (CASE WHEN EN < 0 THEN 28 ELSE 28 - EN END -
CASE WHEN ST <= 0 THEN 0 ELSE 28 - ST END))/CNT SUM
FROM
(SELECT DATEDIFF(FROM_DATE,DATE('2014-02-01'))ST,
DATEDIFF(DATE('2014-03-01'),TO_DATE) - 1 EN,
DATEDIFF(TO_DATE,FROM_DATE) + 1 CNT,TABLE1.* FROM TABLE1)T1;

SQL Fiddle