Oracle query with every minute a day

Question

I want to write a query in oracle sql, which returns every minute of the current day in one column. But i've got no idea, how to start :-(

min
27.03.2014 00:00
27.03.2014 00:01
27.03.2014 00:02
...
27.03.2014 23:59

Thanks

Answer 1

We can use arithmetic to manipulate dates, and the simple CONNECT BY trick to generate a stream of rows.

alter session set nls_date_format='dd-mon-yyyy hh24:mi'
/

with cte as ( select trunc(sysdate) as start_date from dual )
select start_date + ((level-1)/(24*60)) as date_w_mins
from cte
connect by level <= (24*60)
/

Answer 2

You can use numtodsinterval function and is simple too:

SELECT to_char(TRUNC(sysdate)+ 
               numtodsinterval (level-1,'minute'),'dd.mm.yyyy hh24:mi') min
FROM dual
CONNECT BY LEVEL <= (24*60);

Answer 3

SELECT date + minute FROM
(
SELECT TO_DATE('yyyy.mm.dd', '2014.03.27') date FROM DUAL
CROSS JOIN
( 
SELECT 0 minute FROM DUAL
UNION ALL
SELECT rownum r
FROM DUAL
CONNECT BY rownum <= 1439
) T
) TT