If you already have the String
, a substring
would do the work:
date = date.substring(0,10);
Domanda
I am getting this 14-03-2014 09:02:10
string from JSON. All is OK but I want just the date part in this string not the time (14-03-2014)
. So how can I convert the string to this format.
Soluzione
If you already have the String
, a substring
would do the work:
date = date.substring(0,10);
Altri suggerimenti
You just try this solution i hope it will useful for you just give the date format into one you can get the desired one...
String inputPattern = "yyyy-MM-dd hh:mm:ss";
String outputPattern = "dd/MM";
SimpleDateFormat inFormat = new SimpleDateFormat(inputPattern);
SimpleDateFormat outputFormat = new SimpleDateFormat(outputPattern);
Date date1 = null;
if (date != null) {
try {
date1 = inFormat.parse(date);
str = outputFormat.format(date1);
Log.d(null, str);
} catch (ParseException e) {
e.printStackTrace();
}
} else {
str = " ";
}
You can use Split() method for extract date part from String
String str = "14-03-2014 09:02:10"
String [] part = str.split(" ");
String date = part[0];
Or you can also use substring()
method if your date field's size is constant, i.e. for 01 instead of 1 in date part
str = str.substring(0,10);
Use substring
method
String jsonString = "14-03-2014 09:02:10";
if(jsonString.contains(" ")){
String onlyDate = string.substring(0, string.indexOf(" "));
}
Try this...
public class Test {
public static void main(String a[])
{
String date_time = "14-03-2014 09:02:10";
String[] split_val = date_time.split(" ");
String date = split_val[0];
String time = split_val[1];
System.out.println(date+"--------------"+time);
}
}
Use the below code
String date="14-03-2014 09:02:10";
String reqdate=date.substring(0,10);