Domanda

This is my scenario:

I have a build.bat that holds:

call tools\nant-0.92\bin\nant.exe -buildfile:deploy.build %* -logfile:deploy_NAnt.log

Part of deploy.build holds:

<project 
    name="EdpClient" 
    basedir="." default="build" 
    xmlns="http://nant.sf.net/release/0.92/nantContrib.xsd">
        <!--INIT -->
        ...
        <property name="version" value="1.48.0.4" />
        ...
        <!--RELEVANT TARGET-->
        <target name="BuildProductionApplication" description="Build">
            <property 
                name="publishFolderParameter" 
                value="/p:PublishDir=${productionPublishFolder}" />
            <echo message="Building..." />  
            <exec 
                program="${msbuildExe}" 
                workingdir="." verbose="true">
                    <arg value="${projectFile}" />
                    <arg value="/target:Clean;Publish" />
                    <arg value="${publishFolderParameter}" />
                    <arg value="/property:ApplicationVersion=${version}" />
                    <arg value="/property:PublisherName=&quot;${publisherName}&quot;" />
            </exec>
            <echo message="Built" />
        </target>
    ...
</project>

Now my question is:

  • How can i call "build.bat -version 1.48.0.4" and replace the param in my structure?
  • If the -version param is not supplied the script should throw some sort of msg back in command line?

Thanks to all that help!

È stato utile?

Soluzione

This is how i did it:

In deploy.build file i changed:

<property name="version" value="1.48.0.4" />

to:

<property name="version" value="${arg.version}" />

And this is how build.bat (batch) looks like now:

@ECHO OFF
IF %1.==. GOTO ERROR
ECHO:BUILDING VERSION: %1 ...
CALL tools\nant-0.92\bin\nant.exe -buildfile:deploy.build -D:arg.version=%1 -logfile:deploy_NAnt.log
GOTO END
:ERROR
ECHO.
ECHO Please provide the version parameter (eg. "deploy 1.1.1.1")
ECHO.
GOTO END
:END

Now I can call build 1.48.0.4 command. It suits all my needs.

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