URL Encode in J2ME?

Question

I have a problem while working in a project when i'm trying to parse a String to URL so can i send my HttpRequest.The problem is that couldn't convert the String and i'm getting

java.lang.IllegalArgumentException: no ':' in URL

This is the method i'm using

 public String getResultat()  throws Exception {


     /// CODE J2ME

     int ch;
        StringBuffer sb = new StringBuffer("");
        HttpConnection ht;
        DataInputStream ds;
        try {

       String chx="http:x.com";

       String ecodedString=EnvoyerSMS.urlEncode(chx);

            ht = (HttpConnection) Connector.open(ecodedString);
            ds = ht.openDataInputStream();
            while ((ch = ds.read()) != -1) {
                sb.append((char)ch);
            }
        } catch (IOException ex) {
            ex.printStackTrace();
        }
        String reponse = sb.toString().trim();
        System.out.println("REPONSE "+reponse);
        return  reponse;
        }

And this is the static method that i used to convert my String

    public static String urlEncode(String s) {
    StringBuffer sbuf = new StringBuffer();
    int len = s.length();
    for (int i = 0; i < len; i++) {
        int ch = s.charAt(i);
        if ('A' <= ch && ch <= 'Z') { // 'A'..'Z'
            sbuf.append((char)ch);
        } else if ('a' <= ch && ch <= 'z') { // 'a'..'z'
            sbuf.append((char)ch);
        } else if ('0' <= ch && ch <= '9') { // '0'..'9'
            sbuf.append((char)ch);
        } else if (ch == ' ') { // space
            sbuf.append('+');
        } else if (ch == '-' || ch == '_'   //these characters don't need encoding
                || ch == '.' || ch == '*') {
            sbuf.append((char)ch);
        } else if (ch <= 0x007f) { // other ASCII
            sbuf.append(hex(ch));
        } else if (ch <= 0x07FF) { // non-ASCII <= 0x7FF
            sbuf.append(hex(0xc0 | (ch >> 6)));
            sbuf.append(hex(0x80 | (ch & 0x3F)));
        } else { // 0x7FF < ch <= 0xFFFF
            sbuf.append(hex(0xe0 | (ch >> 12)));
            sbuf.append(hex(0x80 | ((ch >> 6) & 0x3F)));
            sbuf.append(hex(0x80 | (ch & 0x3F)));
        }
    }
    return sbuf.toString();
}

    //get the encoded value of a single symbol, each return value is 3 characters long
static String hex(int sym)
 {
     return(hex.substring(sym*3, sym*3 + 3));
 }

// Hex constants concatenated into a string, messy but efficient
final static String hex =
"%00%01%02%03%04%05%06%07%08%09%0a%0b%0c%0d%0e%0f%10%11%12%13%14%15%16%17%18%19%1a%1b%1c%1d%1e%1f" +
"%20%21%22%23%24%25%26%27%28%29%2a%2b%2c%2d%2e%2f%30%31%32%33%34%35%36%37%38%39%3a%3b%3c%3d%3e%3f" +
"%40%41%42%43%44%45%46%47%48%49%4a%4b%4c%4d%4e%4f%50%51%52%53%54%55%56%57%58%59%5a%5b%5c%5d%5e%5f" +
"%60%61%62%63%64%65%66%67%68%69%6a%6b%6c%6d%6e%6f%70%71%72%73%74%75%76%77%78%79%7a%7b%7c%7d%7e%7f" +
"%80%81%82%83%84%85%86%87%88%89%8a%8b%8c%8d%8e%8f%90%91%92%93%94%95%96%97%98%99%9a%9b%9c%9d%9e%9f" +
"%a0%a1%a2%a3%a4%a5%a6%a7%a8%a9%aa%ab%ac%ad%ae%af%b0%b1%b2%b3%b4%b5%b6%b7%b8%b9%ba%bb%bc%bd%be%bf" +
"%c0%c1%c2%c3%c4%c5%c6%c7%c8%c9%ca%cb%cc%cd%ce%cf%d0%d1%d2%d3%d4%d5%d6%d7%d8%d9%da%db%dc%dd%de%df" +
"%e0%e1%e2%e3%e4%e5%e6%e7%e8%e9%ea%eb%ec%ed%ee%ef%f0%f1%f2%f3%f4%f5%f6%f7%f8%f9%fa%fb%fc%fd%fe%ff";
}

Thanks :D

Answer 1

URLEncoder is not the equivalent of the code you have written. The equivalent of that is

new URI(null, string, null).toASCIIString()

Despite its name, URLEncoder isn't for encoding URLs. It is for encoding URL arguments, and POST key-value pairs.

Answer 2

Shouldn't it be http://x.com rather than http:x.com ?

Bu tif you have a really simple URL like that (i.e., with no parameters) you won't need to encode it at all.

However, suppose your URL does contain parameters - e.g., http://x.com?param1=value1&param2=value2, then you would encode just the parameter values like this:

String encodedString = "http://x.com?param1=" + EnvoyerSMS.urlEncode(value1) + "&param2=" + EnvoyerSMS.urlEncode(value2);

...but use a StringBuffer to concatenate these parts rather than using the + operator like I have.

NB - The reason you were getting the no ':' in URL error is because you had erroneously encoded the entire URL, so the : character was also encoded (into whatever its encoded equivalent is).

If you do System.out.println(encodedString); you will see what URL your HttpConnection object is trying to work with.