how to use the = operator as you create a new object?

Question

I have an object and I have overloaded the = operator to accept an int.

class jakeint
{
private:
    vector<short> theInt;
    void _setFromInt(int x);

    //operators
public:
    jakeint& jakeint::operator=(int x)
    {
        _setFromInt(x);
        return *this;
    }
};

This works perfectly fine. The problem is that if I want to use the = operator, I have to do this:

jakeint ji;
ji = 8;

I do want this to be doable, but I also would like to be able to do this:

jakeint ji = 8;

How would I go about doing this?

I realize I could just add it to the constructor and do

jakeint ji(8);

but I want these to work just like integers do.

Answer 1

Create a constructor with an argument of type int.

jakeint(int x)
{
  _setFromInt(x);
}

With that, you could use:

jakeint ji = 8;

as well as

jakeint ji(8);

Answer 2

Just add it to the constructor. You can specify the initialization with = or not, it doesn't matter. It invokes the constructor either way.

Answer 3

You can make a constructor with argument for jakeint ji = 8; and jakeint ji(8);, such as:

jakeint(int x) {
    _setFromInt(x);
}

And if you define a constructor by yourself, you need to define a default constructor too if you still want to use jakeint ji;, such as:

jakeint() {
    _setFromInt(0);
}

Answer 4

You need a constructor that takes an int, and also a copy constructor. The implicit copy constructor is fine in this case. (The actual call to the copy ctor is usually elided.)

Answer 5

jakeint ji = 8; is just a shorthand alias for jakeint ji(8);, they are identical, so you do need to add a constructor that takes an int as input, as other people have showed you.