You can't really do it in lambda with expression since you need to eat return value. Try use statement block instead:
Assert.Throws<MyException>(() => { object shouldFail = myobj[fakeField];});
Note: it is not recommended to throw from get
...
Domanda
I wish to use Assert.Throws
with a property get.
E.g.
object shouldFail = myobj[fakeField];
my attempts, albeit bad ones to help demonstrate my need.
Assert.Throws<MyException>(() => object shouldFail = myobj[fakeField]);
Assert.Throws<MyException>(() => myobj[fakeField]);
The syntax error I get is
Only assignment, call, decrement, and new object expressions can be used as a statement
. I understand that. So I am asking without a try/catch, how can I test for an exception on that line of code in the e.g. above?
I am aware of [ExpectedException(typeof(MyException))]
Soluzione
You can't really do it in lambda with expression since you need to eat return value. Try use statement block instead:
Assert.Throws<MyException>(() => { object shouldFail = myobj[fakeField];});
Note: it is not recommended to throw from get
...