Domanda

I have a JTextArea which only has to accept numbers. This is my code:

DocumentFilter onlyNumberFilter = new AxisJTextFilter();
    final JTextArea areaTextoXMin = new JTextArea(String.valueOf(xMin));
    ((AbstractDocument)areaTextoXMin.getDocument()).setDocumentFilter(onlyNumberFilter);

Works OK for positive numbers, but not for negative numbers. How can I fix that?

EDIT: Sorry, the AxisJTextFilter was found over the Internet and I forgot about that. Its code is:

import javax.swing.text.*;
import java.util.regex.*;

public class AxisJTextFilter extends DocumentFilter
{
    public void insertString(DocumentFilter.FilterBypass fb, int offset, String text, AttributeSet attr) throws BadLocationException
    {
        StringBuilder sb = new StringBuilder();
        sb.append(fb.getDocument().getText(0, fb.getDocument().getLength()));
        sb.insert(offset, text);
        if(!containsOnlyNumbers(sb.toString())) return;
        fb.insertString(offset, text, attr);
    }
    public void replace(DocumentFilter.FilterBypass fb, int offset, int length, String text, AttributeSet attr) throws BadLocationException
    {
        StringBuilder sb = new StringBuilder();
        sb.append(fb.getDocument().getText(0, fb.getDocument().getLength()));
        sb.replace(offset, offset + length, text);
        if(!containsOnlyNumbers(sb.toString())) return;
        fb.replace(offset, length, text, attr);
    }
    public boolean containsOnlyNumbers(String text)
    {
        Pattern pattern = Pattern.compile("\\d*(\\.\\d{0,3})?");
        Matcher matcher = pattern.matcher(text);
        boolean isMatch = matcher.matches();
        return isMatch;
    }
}
È stato utile?

Soluzione

Try modifying the regular expression (int the validation method containsOnlyNumbers).

Pattern pattern = Pattern.compile("^[\\-\\+]?\\d+(\\.\\d+)?$");

This will accept the following numbers:

  • 1234
  • -1234
  • +1234
  • 1234.1234

I hope it helps

Udi

Altri suggerimenti

This is intended as a comment on Udi's excellent post, but I can't figure out how to do that.

I think his pattern (d+) requires at least 1 digit, and it should be d? to allow 0-N digits. Because, as the user is typing, "-" is legal input. And a decimal point followed by no digits is always legal, especially while typing. It's only at the end (when you lose focus, etc., YMMV) that you can either require at least one digit, or, be accommodating and pragmatic and just treat the string "-" as 0.

And when developing these kinds of regular expressions don't forget that the user might be copying and pasting.

Autorizzato sotto: CC-BY-SA insieme a attribuzione
Non affiliato a StackOverflow
scroll top