Multiple statement conditions using OR AND within the query

Question

I have this survey table and I'm trying to gather the information of userid who answer Strongly agree to the question of I'm trying to watch my weight OR I love drinking Coffee Black AND must have answer Agree OR Neutral OR Strongly Disagree to these questions I thrive when a deadline is close and I'm all about trying something new.

UserId                QUESTION                               Answer
 1010            I am trying to watch my weight           Strongly Agree
 1120            I thrive when a deadline is close        Strongly Agree
 1120           I'm all about trying something new        Neutral
 2025            I'm all about trying something new       Agree
 3024            I love drinking Coffee Black             Strongly Disagree
 3024            I'm all about trying something new       Agree

The queries that I tried to write keeps returning the questions that I didn't write.This might not be the best way write such query but I'm learning on how to properly write those. Any help would be appreciated.

 SELECT userid_
  ,QUESTION 
  ,answer
   FROM [Survey_2019]]

Where QUESTION  = 'I'm trying to watch my weight'  AND
    Answer =  'Strongly agree'
  OR
      QUESTION    = 'I love drinking Coffee Black
  AND 
 Answer =  'Strongly agree'

AND 

 QUESTION= 'I thrive when a deadline is close'
  AND ANSWER= 'Agree' 
OR 'Neutral' OR 'Strongly Disagree'

Answer 1

I have this survey table and I'm trying to gather the information of userid who answer Strongly agree to the question of I'm trying to watch my weight OR I love drinking Coffee Black AND must have answer Agree OR Neutral OR Strongly Disagree to these questions I thrive when a deadline is close and I'm all about trying something new.

Simplified:

          [     A:a        ON     (Q:a/b)   ]
    AND   [  (A:b/c/d)     ON       Q:c     ] 
    AND   [  (A:b/c/d)     ON       Q:d     ]

In SQL:

SELECT UserId
FROM Survey_2019
GROUP BY UserId
HAVING SUM (CASE WHEN Question IN ('a', 'b') AND Answer = 'a' THEN 1 END) > 0
   AND SUM (CASE WHEN Question = 'c' AND Answer IN ('b', 'c', 'd') THEN 1 END) > 0
   AND SUM (CASE WHEN Question = 'd' AND Answer IN ('b', 'c', 'd') THEN 1 END) > 0

If you need separate records matched then use this SQL as CTE/subquery and select separate records from another copy of source table.

UPDATE

It seems that last 2 conditions may be combined into one using simplified condition

    AND   [  (A:b/c/d)     ON       Q:c/d     ] 

But the problem is to ensure that all (2 in that case) questions are mentioned. Yes, this is possible and can be performed using, for example

   AND COUNT(DISTINCT CASE WHEN Question IN ('c','d') 
                            AND Answer IN ('b', 'c', 'd') 
                           THEN Question 
                           END) = 2

If you need to ensure that there is no a record with the question(s) in interest and the answer not in list, then use additional condition similar to

   AND COUNT(CASE WHEN Question IN ('c','d') 
                   AND Answer NOT IN ('b', 'c', 'd') 
                  THEN 1
                  END) = 0

Answer 2

For a start: You are missing a number of parentheses (in any case).

Then: You need to combine different records into a single result. One way has been shown by @Akina. Alternatively, you can run against two copies of the same table:

WITH
Part1 AS (
  SELECT
    userID
    , question
    , answer
  FROM Survey_2019
  WHERE
    question IN ('I am trying to watch my weight', 'I love drinking Coffee Black')
    AND
    answer = 'Strongly Agree'
),
Part2 AS (
  SELECT
    userID
    , question
    , answer
  FROM Survey_2019
  WHERE
    question IN ('I thrive when a deadline is close', 'I''m all about trying something new')
    AND
    answer IN ('Agree', 'Neutral', 'Strongly Disagree')
),
Overview (userID, question1, answer1, question2, answer2) AS (
  SELECT
    Part1.userID
    , Part1.question
    , Part1.answer
    , Part2.question
    , Part2.answer
  FROM Part1
  JOIN Part2
    ON Part1.userID = Part2.userID
)
SELECT
  * FROM Overview ORDER BY userID, question1, question2
;

See it in action: SQL Fiddle (Two records have been added to your sample data for an actual match.)

Akina's approach as detailed is more appropriate, if you care primarily for a list of users, for which the conditions are met. (But you can, of course, extend it along Akina's suggestion.) Mine provides directly all the details - but might become hard to swallow, if your data might be such as to produces multiple matches for a some user(s).

There is, however, a difference in Akina's an my reading of what is in Part2 of my approach: Akina expects an answer to both of the questions, I'd be satisfied, if at least one of the was answered. - You'll know best, which one is correct. (Both SQL statements can be adjusted accordingly.)

Your table design is probably/hopefully still under development… ;-)

Please comment, if and as this requires adjustment / further detail.