How can I find all the rows in a table that exclusively have related rows in a given list?
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28-05-2021 - |
Domanda
I have three tables. Think of them as the following:
Recipes
id | name
1 | Cookies
2 | Soup
...
Ingredients
id | name
1 | flour
2 | butter
3 | chicken
...
Recipe_Ingredient
recipe_id | ingredient_id
1 | 1
1 | 2
2 | 3
Hopefully you get the idea. What I'd like is a query where I can find all recipes that have ingredients that are a subset of a given set of ingredients.
The idea being that I'd like to have a list of all the things I can make with what I have on hand (but of course not EVERYTHING I have on hand.)
I tried implementing this with various levels of subqueries and correlated subqueries with EXISTS but had no luck. I also tried to use HAVING and COUNT, but that only seems to work for me if I want something that uses ALL the ingredients I have on hand.
Soluzione
Test this if it works. Assuming that you have your (unique) ingredient ids available in a table called ingredients_avail, this query should show the recipe id that has complete ingredients:
SELECT recipe_id
FROM [select recipe_id, count(*) as num_of_ingredients from recipe_ingredient group by recipe_id]. AS x, [select recipe_ingredient.recipe_id as recipe_id, count(*) as num_of_ingredients
from recipe_ingredient, ingredients_avail
where
recipe_ingredient.ingredient_id = ingredients_avail.ingredient_id
group by recipe_ingredient.recipe_id]. AS y
WHERE x.recipe_id = y.recipe_id and
x.num_of_ingredients = y.num_of_ingredients;
Additionally, here it is in a more typical syntax:
SELECT x.recipe_id
FROM (
SELECT recipe_id, count(*) as num_of_ingredients
FROM recipe_ingredients
GROUP BY recipe_id
) x, (
SELECT recipe_id, count(*) as num_of_ingredients
FROM recipe_ingredients
JOIN ingredients_avail
ON recipe_ingredients.ingredient_id = ingredients_avail.ingredient_id
GROUP BY recipe_id
) y
WHERE x.recipe_id = y.recipe_id AND x.num_of_ingredients = y.num_of_ingredients;
Altri suggerimenti
mysql>
mysql> select * from ingredients;
+------+---------------+-----------+
| id | name | available |
+------+---------------+-----------+
| 1 | salt | n |
| 2 | sugar | n |
| 3 | flour | n |
| 4 | butter | n |
| 5 | vanilla | n |
| 6 | baking powder | n |
| 7 | egg | n |
+------+---------------+-----------+
7 rows in set (0.00 sec)
mysql> select * from recipes;
+------+---------------+
| id | name |
+------+---------------+
| 1 | cookie |
| 2 | soup |
| 3 | xtreme flavor |
+------+---------------+
3 rows in set (0.00 sec)
mysql> select * from recipe_ingredient;
+-----------+---------------+
| recipe_id | ingredient_id |
+-----------+---------------+
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 1 | 4 |
| 1 | 5 |
| 1 | 6 |
| 1 | 7 |
| 2 | 1 |
| 2 | 7 |
| 3 | 4 |
| 3 | 3 |
+-----------+---------------+
11 rows in set (0.00 sec)
mysql>
mysql> update ingredients set available = 'n';
Query OK, 0 rows affected (0.00 sec)
Rows matched: 7 Changed: 0 Warnings: 0
mysql>
mysql> update ingredients set available = 'y'
-> where id in (1,2,3,4,5,6,7);
Query OK, 7 rows affected (0.00 sec)
Rows matched: 7 Changed: 7 Warnings: 0
mysql>
mysql> select recipes.name from
-> (select recipe_id, available from
-> recipe_ingredient,
-> ingredients
-> where ingredient_id = ingredients.id
-> group by recipe_id, available) x, recipes
-> where recipes.id = x.recipe_id
-> group by x.recipe_id
-> having count(*) = 1
-> and max(x.available) = 'y';
+---------------+
| name |
+---------------+
| cookie |
| soup |
| xtreme flavor |
+---------------+
3 rows in set (0.06 sec)
mysql>
mysql> update ingredients set available = 'n';
Query OK, 7 rows affected (0.00 sec)
Rows matched: 7 Changed: 7 Warnings: 0
mysql>
mysql> update ingredients set available = 'y'
-> where id in (1,7);
Query OK, 2 rows affected (0.00 sec)
Rows matched: 2 Changed: 2 Warnings: 0
mysql>
mysql> select recipes.name from
-> (select recipe_id, available from
-> recipe_ingredient,
-> ingredients
-> where ingredient_id = ingredients.id
-> group by recipe_id, available) x, recipes
-> where recipes.id = x.recipe_id
-> group by x.recipe_id
-> having count(*) = 1
-> and max(x.available) = 'y';
+------+
| name |
+------+
| soup |
+------+
1 row in set (0.06 sec)
mysql>
mysql>
mysql> update ingredients set available = 'n';
Query OK, 2 rows affected (0.00 sec)
Rows matched: 7 Changed: 2 Warnings: 0
mysql>
mysql> update ingredients set available = 'y'
-> where id in (4,3);
Query OK, 2 rows affected (0.00 sec)
Rows matched: 2 Changed: 2 Warnings: 0
mysql>
mysql> select recipes.name from
-> (select recipe_id, available from
-> recipe_ingredient,
-> ingredients
-> where ingredient_id = ingredients.id
-> group by recipe_id, available) x, recipes
-> where recipes.id = x.recipe_id
-> group by x.recipe_id
-> having count(*) = 1
-> and max(x.available) = 'y';
+---------------+
| name |
+---------------+
| xtreme flavor |
+---------------+
1 row in set (0.05 sec)
mysql>
mysql>
mysql> update ingredients set available = 'n';
Query OK, 3 rows affected (0.00 sec)
Rows matched: 7 Changed: 3 Warnings: 0
mysql>
mysql> update ingredients set available = 'y'
-> where id in (1,3,7);
Query OK, 3 rows affected (0.00 sec)
Rows matched: 3 Changed: 3 Warnings: 0
mysql>
mysql> select recipes.name from
-> (select recipe_id, available from
-> recipe_ingredient,
-> ingredients
-> where ingredient_id = ingredients.id
-> group by recipe_id, available) x, recipes
-> where recipes.id = x.recipe_id
-> group by x.recipe_id
-> having count(*) = 1
-> and max(x.available) = 'y';
+------+
| name |
+------+
| soup |
+------+
1 row in set (0.06 sec)