Domanda

I've looked for the answer but still can't figure this out.

Sorry, but my work is too complex to copy here sample code.

I have a function, which gets a pointer as parameter; I use it, but later, I need a kind of callback, where I want to use my old pointed object.

The problem is, when this callback is invoked, the pointer has already been deleted or freed. My idea was to make a copy of the pointed object on the heap, and free it when callback is finished. But I got lost between pointers, copy constructors and other stuff. The solution is probably quite simple, but I'm stuck.

È stato utile?

Soluzione

Suppose you have a type T, and a pointer T* ptr; Assuming ptr is currently a valid pointer, then T* ptr2 = new T(*ptr); should invoke the copy constructor on T to create a new pointer on the heap. Now, this requires that your type T has a correctly written copy constructor and destructor and the like.

Altri suggerimenti

If you have a T * p, then you can make a new object like so:

T x(*p);

Or, if you must (but seriously, don't!), a dynamically allocated object:

T * q = new T(*p);

Don't use the second form. There's no end to the headache you're inviting with that.

I just found this: C++ Idioms/Virtual Constructor

Another way to do it:

MyObject* pointerFromOld;
...
MyObject newObject = *pointerFromOld;

Asterisk before a pointer returns the object it points to (interprets the contents of the address as the object), while assigning that object to newObject makes its copy.

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