We only need to check if there is any ON bit higher than the 53rd bit, or higher than the 21st bit of the high 32-bit part.
Just take the high 32-bit and &
with ~((1 << 21) - 1)
(this will clear all the lower 21-bit of the 32-bit) to check if there is any bit over the limit. The number will be inside the limit if the result is 0.