I discover what I was doing wrong, I had multiplied seconds * 1000 returning a negative int because the result was very big, to correct i did seconds * 1000L.
How can I represent large amount of time using joda-time
Domanda
I'm trying to represent the value 3419779 (in seconds) in hours minutes and seconds however using Period of joda time returns -243h-06min-28, What can I use to represent this in the correct form that would be around 950 hours x min y sec?
I discover what I was doing wrong, I had multiplied seconds * 1000 returning a negative int because the result was very big, to correct i did seconds * 1000L.
Soluzione 2
Altri suggerimenti
The problem is caused by an integer overflow as noted above. Please mark the question as answered.
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