template parsing URL in java

Question

I have a application that receive a message from SMPP server and forward the received message to users web services. all users have a URL in database like this:

http://www.example.com/get.php?from=${originator}&to=${destination}&data=${content}
http://www.example.com/submit?origin=${originator}&dst=${destination}&cnt=${content}

All of them have ${originator},${destination},${content} in their pattern. they may have other parameters in their URL or not. I use Jodd StringTemplateParser to replace above arguments after getting user URL from database:

private StringTemplateParser stp = new StringTemplateParser();
private final Map<String, String> args = new HashMap<>();

args.put("originator", msg.getOriginator());
args.put("destination", msg.getDestination());
args.put("content", msg.getContent());

String result = stp.parse(deliveryUrl, new MacroResolver() {
    @Override
    public String resolve(String macroName) {
        return args.get(macroName);
    }
});

Then I use apache http client to call user URL:

URL url = new URL(result);
int port = url.getPort();
uri = new URI(url.getProtocol(), null, url.getHost(), port == -1 ? 80 : port, url.getPath(), url.getQuery(), null);

DefaultHttpClient client = new DefaultHttpClient();
HttpGet request = null;
try {
    request = new HttpGet(uri);
    client.execute(request)
} catch (Exception ex) {
    if (request != null) {
        request.releaseConnection();
    }
}

I tried to do some encoding because user may send any text containing characters like %$&. The problem is when content contains something like hello&x=2&c=3243 user only gets hello. URI class treats that as regular GET query parameter. Can anyone help?

Answer 1

You need to encode the parameter values when you are building your new URI.

You can encode the parameters using URLEncoder.encode(String).

So, in your MacroResolver, just return URLEncoder.encode(map.get(macroName)).

Answer 2

I think in your case you need to use HTTP default content char-set something like this for your code

request = new HttpGet(url+"?"+URLEncodedUtils.format(namevaluepair, HTTP.DEFAULT_CONTENT_CHARSET));