PHP Convert eregi() string to preg_match or preg_replace [duplicate]

Question

This question already has answers here:

How can I convert ereg expressions to preg in PHP? (4 answers)

Closed 8 years ago.

please can someone help me with convert this string from eregi() to preg_match or preg_replace? Thank you very much!

$eregicheck = "^([-!#\$%&'*+./0-9=?A-Z^_`a-z{|}~])+@([-!#\$%&'*+/0-9=?A-Z^_`a-z{|}~]+\\.)+[a-zA-Z]{2,4}\$";

Answer 1

Sure:

$pregcheck = "(".$eregicheck.")i";

Done.