Domanda

i'm in trouble this is an example of $_FILES['file']['tmp_name']

/Applications/XAMPP/xamppfiles/temp/phpjCag18 

i would like to get the temp binary filename so in this case phpjCag18

Is there anyway to get it from the $_FILES[]?

Ho to get it clean from path ?

È stato utile?

Soluzione 2

If I understand you correctly:

basename($_FILES['file']['tmp_name'])

Altri suggerimenti

You can use basename() for this purpose.

$tmp = $_FILES['file']['tmp_name'];
echo basename( $tmp );

Or, if you're trying to get the extension, use pathinfo():

$extension =  strtolower( pathinfo($_FILES['file']['tmp_name'], PATHINFO_EXTENSION) );
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