Oracle Duration関数
質問
PL / SQL期間関数が正しく機能しないのはなぜですか?以下のクエリでは、以下の関数と同じ方法で「hh:mm」を手動で計算します。ただし、結果は異なります。
クエリの呼び出し:
WITH durdays AS (SELECT SYSDATE - (SYSDATE - (95 / 1440)) AS durdays FROM DUAL)
SELECT TRUNC (24 * durdays) AS durhrs,
MOD (TRUNC (durdays * 1440), 60) AS durmin,
steven.duration (SYSDATE - (95 / 1400), SYSDATE) duration
FROM durdays
出力:
durhrs: 1
durmin: 35
duration: '1:38'
機能コード:
CREATE OR REPLACE FUNCTION steven.duration (d1 IN DATE, d2 IN DATE)
RETURN VARCHAR2 IS
tmpvar VARCHAR2 (30);
durdays NUMBER (20,10); -- Days between two DATEs
durhrs BINARY_INTEGER; -- Completed hours
durmin BINARY_INTEGER; -- Completed minutes
BEGIN
durdays := d2-d1;
durhrs := TRUNC(24 * durdays);
durmin := MOD (TRUNC(durdays * 1440), 60);
tmpvar := durhrs || ':' || durmin;
RETURN tmpvar;
END duration;
/
解決
小さなタイプミスがあるかもしれません:
WITH durdays AS (SELECT SYSDATE - (SYSDATE - (95 / 1440)) AS durdays FROM DUAL)
^^^^
SELECT TRUNC (24 * durdays) AS durhrs,
MOD (TRUNC (durdays * 1440), 60) AS durmin,
lims_sys.duration (SYSDATE - (95 / 1400), SYSDATE) duration
^^^^
これが修正されると問題なく動作します:
SQL> WITH durdays AS (SELECT SYSDATE - (SYSDATE - (95 / 1440)) AS durdays FROM DUAL)
2 SELECT TRUNC (24 * durdays) AS durhrs,
3 MOD (TRUNC (durdays * 1440), 60) AS durmin,
4 duration (SYSDATE - (95 / 1440), SYSDATE) duration
5 FROM durdays
6 ;
DURHRS DURMIN DURATION
---------- ---------- ----------------
1 34 1:34
他のヒント
sql>set time on
その後、次のようなプロンプトが表示されます。
20:24:35 sql> select count(*) from v$session; count(*) ----------- 78 20:24:50 sql>
クエリの継続時間が15秒であることがわかりました
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