Its just an idea to check the value of $aff wether it goes inside if check or not.
$aff = "100";
if (isset($HTTP_RAW_POST_DATA)) {
var_dump($aff);
WriteLog('events',$aff);
}
else{
var_dump($aff);
}
質問
I have this code:
function WriteLog($offer,$values) {
$Filename = "./".$offer.date('Ymd').".txt";
$fh = fopen($Filename, 'a') or die("can't open file");
$filecontent = $values;
$filecontent .= PHP_EOL;
fwrite($fh,$filecontent);
fclose($fh);
}
$aff = "100";
if (isset($HTTP_RAW_POST_DATA)) {
echo $aff;
WriteLog('events',$aff);
}
Here's the problem: The $aff
variable is not accessible. Echoing the $aff
inside the if ISSET
statement doesn't display the value of the $aff
. What's probably causing this? How can I access the value of the $aff
variable? Note that the WriteLog()
function was executed but the $aff
doesn't have a value. Please help me with this. Thanks!
解決
Its just an idea to check the value of $aff wether it goes inside if check or not.
$aff = "100";
if (isset($HTTP_RAW_POST_DATA)) {
var_dump($aff);
WriteLog('events',$aff);
}
else{
var_dump($aff);
}
他のヒント
$HTTP_RAW_POST_DATA
contains the raw POST data.
in your case $HTTP_RAW_POST_DATA
doesn't contain any value, so your if
condition failed and not print the echo $aff;
value.
$aff = "100";
if (isset($HTTP_RAW_POST_DATA)) {
echo $aff;
WriteLog('events',$aff);
}else{
echo "HTTP_RAW_POST_DATA not set";
}
$HTTP_RAW_POST_DATA requires an ini value to be set, using the input stream should work without any special ini settings and is also the 'prefered' method.
you need to use an alternative method
$postData = file_get_contents('php://input')