What's the difference between 'isset()' and '!empty()' in PHP?

Question

I don't understand the difference between isset() and !empty().

Because if a variable has been set, isn't it the same as not being empty?

Answer 1

ISSET checks the variable to see if it has been set. In other words, it checks to see if the variable is any value except NULL or not assigned a value. ISSET returns TRUE if the variable exists and has a value other than NULL. That means variables assigned a "", 0, "0", or FALSE are set, and therefore are TRUE for ISSET.

EMPTY checks to see if a variable is empty. Empty is interpreted as: "" (an empty string), 0 (integer), 0.0 (float)`, "0" (string), NULL, FALSE, array() (an empty array), and "$var;" (a variable declared, but without a value in a class.

Answer 2

Source :http://php.net/manual/en/types.comparisons.phpThis page shows the comparison of the empty(),is_null(),isset().

Answer 3

The type comparison tables gives answer of all question about these operators

http://php.net/manual/en/types.comparisons.php

Answer 4

And one more remark. empty() checks if the variable exists as well. I.e. if we perform empty() to the variable that wasn't declared, we don't receive an error, empty() returns 'true'. Therefore we may avoid isset() if next we need to check if the variable empty.

So

isset($var) && !empty($var)

will be equals to

!empty($var)

Answer 5

isset — Determine if a variable is set and is not NULL.

!empty — Determine whether a variable is NOT empty.

Answer 6

Isset return false if variable has not been set or it is null and return true if variable has been set and not null.

!empty return true if variable has been set and not empty. Empty string, empty array, "0",0 and false are defined as empty.