質問

I have 3 layouts:

activity_main:

<TableLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:id="@+id/table_layout"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    tools:context=".MainActivity" >

</TableLayout>

layout1:

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/linear_layout1"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

</LinearLayout>

and layout2:

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <TextView 
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="a"/>

</LinearLayout>

I want to add layout2 into layout1, after that, add layout1 into activity_main layout. Here my code:

MainActivity:

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    TableLayout table = (TableLayout) findViewById(R.id.table_layout);
    LinearLayout linear = (LinearLayout) findViewById(R.id.linear_layout1);

    for (int i = 0; i < 8; i++) {
        View view = getLayoutInflater().inflate(R.layout.layout2, linear, false);
        linear.addView(view);
        TableRow row = new TableRow(getApplicationContext());
        row.addView(linear);
        table.addView(row);
    }
}

Anh I get a error:

java.lang.IllegalStateException: The specified child already has a parent. You must call remoteView() on the child's parent first

Please help me. Thanks for reading.

My solution: Thank all. I think I fixed it. Here my code:

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    TableLayout table = (TableLayout) findViewById(R.id.tablelayout);
    for (int i = 0; i < 8; i++) {
        LinearLayout linear = (LinearLayout) getLayoutInflater().inflate(R.layout.layout1, table, false);
        View view = getLayoutInflater().inflate(R.layout.layout2, linear, false);
        linear.addView(view);
        TableLayout row = new TableLayout(this);
        row.addView(linear);
        table.addView(row);
    }
}
役に立ちましたか?

解決

The 'activity_main' layout doesn't have any view with id R.id.linear_layout. So the execution of the statement LinearLayout linear = (LinearLayout) findViewById(R.id.linear_layout1); will result in setting linear to null

他のヒント

Try this:

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    TableLayout table = (TableLayout) findViewById(R.id.table_layout);
    LinearLayout linear = getLayoutInflater().inflate(R.layout.layout1, table, false);

    for (int i = 0; i < 8; i++) {
        View view = getLayoutInflater().inflate(R.layout.layout2, linear, false);
        linear.addView(view);
        TableRow row = new TableRow(getApplicationContext());
        row.addView(linear);
        table.addView(row);
    }
}
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