Calculating totals by group

Question

I'm new to SQL and have only been working with it for about 4 months. However I need to build a stored procedure that can calculate the total for like items (using numerical identifier ie. calculate total E.ThisNumber Where E.ThatNumber = 'Whatever')

This is the code I have so far to retrieve the records I need:

SELECT *
FROM BarRevenueByProcedurePriceInfo
WHERE DeptID = '010.4730'
AND SegmentDateTime = '2013-11-30 00:00:00.000'
ORDER BY ProcedureID

Here's the output:

                           ProcedureID/
RowUpdateTime   Dept Code  E.ThatNumber  E.ThisNumber  E.WhatIneed

2013-11-30      010.4730    4200028      108.15       108.15
2013-11-30      010.4730    4200028       18.18       126.33
2013-11-30      010.4730    4200028       63.63       189.81
2013-11-30      010.4730    4200069        5.00         5.00
2013-11-30      010.4730    4200069        5.01        10.01
2013-11-30      010.4730    4200069        6.00        16.01

Notice how the count resets when the E.ThatNumber value is different than the previous entry. Any help would be greatly appreciated. Thank you!

William Harley

Answer 1

Not 100% sure what you need, it might be this:

SELECT *,
       SUM(ThisNumber) OVER (PARTITION BY ProcedureID)
FROM BarRevenueByProcedurePriceInfo
WHERE DeptID = '010.4730'
AND SegmentDateTime = '2013-11-30 00:00:00.000'
ORDER BY ProcedureID

Answer 2

SQL Server 2012 supports the cumulative sum as:

SELECT *,
       sum(thisnumber) over (partition by procedureId order by (select NULL)) as whatIneed
FROM BarRevenueByProcedurePriceInfo
WHERE DeptID = '010.4730' AND
      SegmentDateTime = '2013-11-30 00:00:00.000'
ORDER BY ProcedureID;

In earlier versions, you need to use a correlated subquery or join with aggregation.

By the way, there is no obvious ordering to the rows. If you are doing a cumulative sum, you should really have a column that specifies the order.