Select by an IN clause but should behave like AND [duplicate]

Question

This question already has answers here:

Matching all values in IN clause (2 answers)

Closed 8 years ago.

IN clause works like OR,

select from table where id in (1, 2, 3)

ie selects in case any of the item in group matches (returns if id is 1, 2 or 3).

---

I need something similar, but based on two columns, and it should return only if ColumnA has all the values of ColumnB.

For eg,

  ColumnA         ColumnB
---------------------------
    1               a
    2               b
    3               c

    1               a
    1               b
    1               c


select CoumnA from table where CoumnA in every ColumnB of (a, b, c);
 -> 1 --since only 1 has all a, b and c

select CoumnA from table where CoumnA in every ColumnB of (b);
 -> 1 --since 1 has b
 -> 2 --since 2 has b

And so on. I know in every of is not a proper keyword, I'm just trying to show an example.

I couldn't try anything since I couldn't get my head around this logic.

Answer 1

Try using just IN(a,b,c) Group by id having count(distinct id) = 3.

Answer 2

What about this:

select t1.ColumnA from table t1 where 
exists (select * from table t2 where t1.ColumnA=t2.ColumnA and t2.ColumnB='a')
and exists (select * from table t2 where t1.ColumnA=t2.ColumnA and t2.ColumnB='b')
and exists (select * from table t2 where t1.ColumnA=t2.ColumnA and t2.ColumnB='c')
group by t1.ColumnA