my_str = 'Id:0\t1.0,0.0,83,212,302,475\n'
re.findall('[\d\.]+',my_str)
Out[144]: ['0', '1.0', '0.0', '83', '212', '302', '475']
You could alternately do it like this:
[x.strip('Id:\n') for x in re.split('[\t,]',my_str)]
Out[143]: ['0', '1.0', '0.0', '83', '212', '302', '475']
But that's a little fragile (and harder to read)