Recover the original number from a float

Question

Numbers are being stored in a database (out of my control) as floats/doubles etc.

When I pull them out they are damaged - for example 0.1 will come out (when formatted) as 0.100000001490116119384765625.

Is there a reliable way to recover these numbers?

I have tried new BigDecimal(((Number) o).doubleValue()) and BigDecimal.valueOf(((Number) o).doubleValue()) but these do not work. I still get the damaged result.

I am aware that I could make assumptions on the number of decimal places and round them but this will break for numbers that are deliberately 0.33333333333 for example.

Is there a simple method that will work for most rationals?

I suppose I am asking is there a simple way of finding the most minimal rational number that is within a small delta of a float number?.

Answer 1

Here's the bludgeon way I have done it - I would welcome a more elegant solution.

I chose an implementation of Rational that had a mediant method ready-made for me.

I refactored it to use long instead of int and then added:

// Default delta to apply.
public static final double DELTA = 0.000001;

public static Rational valueOf(double dbl) {
  return valueOf(dbl, DELTA);
}

// Create a good rational for the value within the delta supplied.
public static Rational valueOf(double dbl, double delta) {
    // Primary checks.
    if ( delta <= 0.0 ) {
        throw new IllegalArgumentException("Delta must be > 0.0");
    }
    // Remove the integral part.
    long integral = (long) Math.floor(dbl);
    dbl -= integral;
    // The value we are looking for.
    final Rational d = new Rational((long) ((dbl) / delta), (long) (1 / delta));
    // Min value = d - delta.
    final Rational min = new Rational((long) ((dbl - delta) / delta), (long) (1 / delta));
    // Max value = d + delta.
    final Rational max = new Rational((long) ((dbl + delta) / delta), (long) (1 / delta));
    // Start the fairey sequence.
    Rational l = ZERO;
    Rational h = ONE;
    Rational found = null;
    // Keep slicing until we arrive within the delta range.
    do {
        // Either between min and max -> found it.
        if (found == null && min.compareTo(l) <= 0 && max.compareTo(l) >= 0) {
            found = l;
        }
        if (found == null && min.compareTo(h) <= 0 && max.compareTo(h) >= 0) {
            found = h;
        }
        if (found == null) {
            // Make the mediant.
            Rational m = mediant(l, h);
            // Replace either l or h with mediant.
            if (m.compareTo(d) < 0) {
                l = m;
            } else {
                h = m;
            }
        }

    } while (found == null);

    // Bring back the sign and the integral.
    if (integral != 0) {
        found = found.plus(new Rational(integral, 1));
    }
    // That's me.
    return found;
}    

public BigDecimal toBigDecimal() {
  // Do it to just 4 decimal places.
  return toBigDecimal(4);
}

public BigDecimal toBigDecimal(int digits) {
  // Do it to n decimal places.
  return new BigDecimal(num).divide(new BigDecimal(den), digits, RoundingMode.DOWN).stripTrailingZeros();
}

Essentially - the algorithm starts with a range of 0-1. At each iteration I check to see if either end of the range falls between my d-delta - d+delta range. If it does we've found an answer.

If no answer is found we take the mediant of the two limits and replace one of the limits with it. The limit to replace is chosen to ensure the limits surround d at all times.

This is essentially doing a binary-chop search between 0 and 1 to find the first rational that falls within the desired range.

Mathematically I climb down the Stern-Brocot Tree choosing the branch that keeps me enclosing the desired number until I fall into the desired delta.

NB: I have not finished my testing but it certainly finds 1/10 for my input of 0.100000001490116119384765625 and 1/3 for 1.0/3.0 and the classic 355/113 for π.

Answer 2

you can store the numbers in the database as String and on the retrieval just parseDouble() them. This way the number wont be damaged, it will be same as you store there.

Answer 3

is there a simple way of finding a rational number that is within 0.00001 of a float number?.

This is called rounding.

double d = ((Number) o).doubleValue();
double d2 = Math.round(d * 1e5) / 1e5;
BigDecimal bd = BigDecimal.valueOf(d2);

or you can use BigDecimal to perform the rounding (I avoid using BigDecimal as it is needelessly slow once you know how to use rounding of doubles)

double d = ((Number) o).doubleValue();
BigDecimal bd = BigDecimal.valueOf(d).setScale(5, RoundingMode.HALF_UP);

Note: never use new BigDecimal(double) unless you understand what it does. Most likely BigDecial.valueOf(double) is what you wanted.