pythonanywhere + flask: website just says 'unhandled exception'. How to get debugger to print stack trace?

StackOverflow https://stackoverflow.com/questions/22670403

  •  22-06-2023
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質問

Be forewarned of a triple-newbie threat - new to python, new to python anywhere, new to flask.

[pythonanywhere-root]/mysite/test01.py

# A very simple Flask Hello World app for you to get started with...

from flask import Flask
from flask import render_template # for templating
#from flask import request   # for handling requests eg form post, etc

app = Flask(__name__)
app.debug = True #bshark: turn on debugging, hopefully?

@app.route('/')
#def hello_world():
#    return 'Hello from Flask! wheee!!'
def buildOrg():
    orgname = 'ACME Inc'
    return render_template('index.html', orgname)

And then in [pythonanywhere-root]/templates/index.html

<!doctype html>
<head><title>Test01 App</title></head>
<body>
{% if orgname %}
  <h1>Welcome to {{ orgname }} Projects!</h1>
{% else %}
<p>Aw, the orgname wasn't passed in successfully :-(</p>
{% endif %}
</body>
</html>

When I hit up the site, I get 'Unhandled Exception' :-( How do I get the debugger to at least spit out where I should start looking for the problem?

役に立ちましたか？

解決

The problem is render_template only expects one positional argument, and rest of the arguments are passed as keyword only arguments.So, you need to change your code to:

def buildOrg():
    orgname = 'ACME Inc'
    return render_template('index.html', name=orgname)

For the first part, you can find the error logs under the Web tab on pythonanywhere.com.

他のヒント

You need to also pass your name of orgname variable that is used in your template to render_template.

flask.render_template:

 flask.render_template(template_name_or_list, **context)

    Renders a template from the template folder with the given context.
    Parameters: 
      template_name_or_list – the name of the template to be rendered, 
      or an iterable with template names the first one existing will be rendered
      context – the variables that should be available in the context of the template.

So, change this line:

return render_template('index.html', orgname)

To:

return render_template('index.html', orgname=orgname)
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