質問

I'm creating a method in TypeScript that should receive a jQuery selector as a parameter and I want to make it strongly typed by using DefinitelyTyped. How should my method be like?

Example:

class Foo {
    constructor($el: jQuerySelector) {
    }
}

What should I replace jQuerySelector with?

役に立ちましたか?

解決

e.g. $('div') in the DefinitelyTyped jquery.d.ts is named JQuery.

ライセンス: CC-BY-SA帰属
所属していません StackOverflow
scroll top