質問

I would like to remove an element from a std::vector v using

v.erase( std::remove_if( std::begin(v), std::end(v), pred), std::end(v) );

I know that the removable element (if exist) it must be between index1 and index2. Is there any way to use this information with remove_if?

役に立ちましたか?

解決

If there is just one element to removed it seems the approch to go is to use std::find_if() rather than std::remove_if() and locate the object in the specific range:

auto it = std::find_if(v.begin() + index1, v.begin() + index2, pred);
if (it != v.begin() + index2) {
    v.erase(it);
}

If there are potentially more elements you could use

v.erase(std::remove_if(v.begin() + index1, v.begin() + index2, pred), v.begin() + index2);

You can use v.erase() to remove elements from an internal range.

他のヒント

This will only search between index1 and index2, NOT including either index. It's up to you to make sure the range is still valid.

v.erase( std::remove_if( std::begin(v) + index1 + 1, std::begin(v) + index2, pred), v.begin() + index2);
v.erase( std::remove_if( std::begin(v) + index1, std::begin(v) + index2, pred), std::begin(v) + index2 );
ライセンス: CC-BY-SA帰属
所属していません StackOverflow
scroll top