how to read xml file in linux

Question

I have one xml file as below, I need "en" using some unix command.

        <void method="put">
            <string>LANGUAGE</string>
            <string>en</string>
        </void>    

using below command (got from some link in google),

sed -n '/string/{s/.*<string>//;s/<\/string.*//;p;}' Locale.xml

I am getting output as

LANGUAGE
en

so I used

sed -n '/string/{s/.*<string>//;s/<\/string.*//;p;}' Locale.xml | tail -1

But is there any option in sed by which I can get second value only?

Answer 1

You can use this sed,

sed -n '/LANGUAGE/{N; s/.*<string>\(.*\)<\/string>.*/\1/p; }' Locale.xml

Answer 2

Use xmlstarlet.

$ cat x.xml 
<?xml version="1.0"?>
<void method="put">
  <string>LANGUAGE</string>
  <string>en</string>
</void>
$ xmlstarlet sel -t -c '/void/string[2]/text()' x.xml
en

Or use xmllint.

$ xmllint --xpath '/void/string[2]/text()' x.xml
en

More about XPath.

Answer 3

You can search for LANGUAGE and the print next line:

awk -F"[<>]" '/LANGUAGE/ {getline;print $3}' Locale.xml 
en

Or search for string and print the last one:

awk -F"[<>]" '/string/ {f=$3} END {print f}' Locale.xml
en

Answer 4

Using xsh:

open file.xml ;
echo //void[string="LANGUAGE"]/string[2]