I think this should do the trick
'FREE_ROOM_COUNT' => array(
self::STAT ,
'Floor' ,
'house_id'
'select' => 'count(rt.floor_id)' , // or count(rt.room_id)
'join' => 'Inner join room_table rt ON Floor.floor_id = rt.floor_id' ,
),
質問
Basically, I have 3 tables.
house_table
===========
house_id
floor_table
===========
floor_id
house_id
room_table
===========
room_id
floor_id
is_occupied
A house has many floor, a floor has many rooms. A room belongs to one floor, a floor belongs to one house. The corresponding models created automatically by gii are HouseTable
, FloorTable
, RoomTable
.
What I need is to findAll()
houses that have rooms that are not occupied.
How do I do that? Something like this?
class HouseRecord extends CActiveRecord {
public function relations() {
return array(
'FREE_ROOM_COUNT' => array(self::STAT ...???...),
);
}
}
Sure, I could do it with SQL, but it needs to be done this way, because the result of findAll()
is used as a data provider in a grid.
UPDATE
Following tinybyte's advice, here's what finally worked.
public function relations() {
return array(
'FREE_ROOM_COUNT' => array(
self::STAT ,
'FloorTable',
'house_id',
'select' => 'COUNT(rt.floor_id)',
'join' => 'INNER JOIN room_table rt ON t.floor_id = rt.floor_id',
'condition' => 'rt.is_occupied = 0',
),
);
}
And to be used as so:
$criteria = new CDbCriteria;
$criteria->with = array('FREE_ROOM_COUNT');
$criteria->together = true;
$provider = new CActiveDataProvider(HouseTable::model(), array(
'criteria'=>$criteria,
'pagination' => array(
'pageSize' => 1,
),
));
$this->widget('zii.widgets.CListView', array(
'dataProvider'=>$provider,
'itemView'=>'house',
));
Unfortunately it turns out one can not use these STAT relations as conditions! (Confirmed here: Using STAT relation in CActiveDataProvider criteria).
解決
I think this should do the trick
'FREE_ROOM_COUNT' => array(
self::STAT ,
'Floor' ,
'house_id'
'select' => 'count(rt.floor_id)' , // or count(rt.room_id)
'join' => 'Inner join room_table rt ON Floor.floor_id = rt.floor_id' ,
),