You are always passing the same address to inserir_inicio()
(the n
).
Every time you change the contents of n
all the nota
pointers in the list all point to the new contents.
You may need to copy the input to brand new objects.
質問
#include <stdio.h>
#include <stdlib.h>
typedef struct lista
{
char instrumento;
char *nota;
int inst;
struct lista *prox;
}melodia;/*com typdef basta usar t_melodia não é preciso usar struct melodia*/
melodia *inicio, *fim; ///dois apontadores para definir o inico e o fim da lista
void inserir_inicio(char *v)
{
if(inicio==NULL)
{
inicio = malloc(sizeof(melodia));
inicio->nota = v;///nota fica com o valor recebido
inicio->prox = NULL;///colocamos o prox para NULL
fim = inicio;
}
else
{
melodia *temp = malloc(sizeof(melodia));
temp->nota = v;
temp->prox = inicio;
inicio = temp; /// Colocamos o novo elemento no inicio
}
printf("Inserido no inicio\n");
}
void imprimir_lista()
{
melodia *aux = inicio;
printf("Lista:\n");
while(aux!=NULL)
{
printf("%s", aux->nota);
aux = aux->prox; /// proximo
}
printf("\n\n");
}
int main()
{
int i = 0;
char n[100];
while(i<5)
{
scanf("%s",n);
inserir_inicio(n);
i++;
}
imprimir_lista();
}
I think the problem is in my function imprimir_lista, i just can´t get it to print to the console the values i insert in the list....(the code is in portuguese if you are asking yourselves, and sorry for my english)
解決
You are always passing the same address to inserir_inicio()
(the n
).
Every time you change the contents of n
all the nota
pointers in the list all point to the new contents.
You may need to copy the input to brand new objects.