How do I match all occurrences of a specific pattern in Regex?

Question

I cant find regex expression of <#anystring#>?

Ex: <#sda#> or <#32dwdwwd#> or any of string between <# and #>

I tried "<#[^<#]+#>" but this has outputted only the first occurrence.

        string sample = "\n\n<#sample01#> jus some words <#sample02#> <#sample03#> just some words ";
        Match match = Regex.Match(sample, "<#[^<#]+#>");
        if (match.Success)
        {
            foreach (Capture capture in match.Captures)
            {
                Console.WriteLine(capture.Value);
            }
        }

Answer 1

You are using the match() method. Try reading the documentation and you will see, that it returns only the first match.

Try the matches() method instead, it returns a MatchCollection.

It would look something like this (careful, not tested written directly here)

string sample = "\n\n<#sample01#> jus some words <#sample02#> <#sample03#> just some words ";
    MatchCollection mc = Regex.Matches(sample, "<#(.*?)#>");
    foreach (Match m in mc)
        {
            Console.WriteLine(m.Groups[0]);
        }
    }

Answer 2

try this one , it should work

UPDATED

<#(.*?)#>

• The dot is any character except new line (\n).
• The * means 0 or more.
• The ? is used to make it ungreedy.

source here