2 issues I see here:
- You are using an empty character class
[]
- Backslash needs more escaping
You can use this regex:
[Ss]([0-9]+)[ ._-]*[Ee]([0-9]+)([^\\\\/]*)$
質問
I am using this regex expression
:
[Ss]([0-9]+)[][ ._-]*[Ee]([0-9]+)([^\\/]*)$
It throws an exception when I am converting into a pattern
:
pattern = Pattern.compile(regExp.get(i));
05-15 11:16:06.914: E/AndroidRuntime(5268): java.util.regex.PatternSyntaxException: Missing closing bracket in character class near index 43:
05-15 11:16:06.914: E/AndroidRuntime(5268): [Ss]([0-9]+)[][ ._-]*[Ee]([0-9]+)([^\\/]*)$
05-15 11:16:06.914: E/AndroidRuntime(5268): ^
05-15 11:16:06.914: E/AndroidRuntime(5268): at java.util.regex.Pattern.compileImpl(Native Method)
05-15 11:16:06.914: E/AndroidRuntime(5268): at java.util.regex.Pattern.compile(Pattern.java:400)
05-15 11:16:06.914: E/AndroidRuntime(5268): at java.util.regex.Pattern.<init>(Pattern.java:383)
05-15 11:16:06.914: E/AndroidRuntime(5268): at java.util.regex.Pattern.compile(Pattern.java:374)
It works fine when running on a java regex tester
. I believe I need to escape some characters here..
解決
2 issues I see here:
[]
You can use this regex:
[Ss]([0-9]+)[ ._-]*[Ee]([0-9]+)([^\\\\/]*)$