http request from iOS

Question

I am trying to send a request to

"http://www.geocodefarm.com/api/forward/json/f0e3d8f953e83ca08c1eb487c64f9b3ecc379d5c/530 W Main St Anoka MN 55303 US/"
which returns a JSON.

Pasting the address in my browser returns a JSON, I just don't know how to do it in iOS

I tried the following in AFNetworking, but the return was:

Error Domain=NSURLErrorDomain Code=-1000 "bad URL" UserInfo=0x14930080 {
NSUnderlyingError=0x14753ac0 "bad URL", NSLocalizedDescription=bad URL}

code:

    url = [NSURL URLWithString:"http://www.geocodefarm.com/api/forward/json/f0e3d8f953e83ca08c1eb487c64f9b3ecc379d5c/530 W Main St Anoka MN 55303 US/"];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
AFHTTPRequestOperation *operation = [[AFHTTPRequestOperation alloc]
                                                 initWithRequest:request];
[operation setCompletionBlockWithSuccess:^(AFHTTPRequestOperation *operation , id responseObject) {
    NSLog(@"%@",responseObject);
                } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"%@",error);
                // code
            }];
[operation start];

Thanks

Answer 1

Your problem most likely relies on your URL. All URLs used in NSURLRequest should be escaped. Try to escape your URL before using it:

NSString* yourURLString = @"http://www.geocodefarm.com/api/forward/json/f0e3d8f953e83ca08c1eb487c64f9b3ecc379d5c/530 W Main St Anoka MN 55303 US/";
NSString* escapedUrlString =[yourURLString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
url = [NSURL URLWithString:escapedUrlString];

Answer 2

Use Following code for request,

NSString *aStr=@"http://www.geocodefarm.com/api/forward/json/f0e3d8f953e83ca08c1eb487c64f9b3ecc379d5c/530 W Main St Anoka MN 55303 US/";
NSString* aStrFinal =[aStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *aUrl=[NSURL URLWithString:aStrFinal];
NSURLRequest *aREquest=[NSURLRequest requestWithURL:aUrl];
[NSURLConnection connectionWithRequest:aREquest delegate:self];

And get response in following code,

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{

NSMutableDictionary* json = [NSJSONSerialization
                        JSONObjectWithData:data //1

                        options:kNilOptions
                        error:nil];
  NSLog(@"json===%@",json);
}

Answer 3

Do like this,

First, create a string to store the string

NSString *strigURL=[NSString stringWithFormat:@"http://www.geocodefarm.com/api/forward/json/f0e3d8f953e83ca08c1eb487c64f9b3ecc379d5c/530 W Main St Anoka MN 55303 US/"];  

Initialise an object for NSURL

NSURL *url=[NSURL URLWithString:strigURL];  

To request

NSMutableURLRequest * request=[NSMutableURLRequest requestWithURL:url];
NSError *error;
NSURLResponse * response;  

the data received from response

NSData * responseData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];  

Encoded data

 output=[[NSString alloc]initWithData:responseData encoding:NSASCIIStringEncoding];
NSLog(@"Response : %@",output);