Ruby integer enumerator with offset

Question

Is there a better/cleaner way to create a Ruby enumerator (i.e. for a for loop) that begins with an offset? A way that only involves the number of times and the offset once.

For example, iterate 10 times starting at 100:

> 100.upto(100 + 10)
#<Enumerator: 100:upto(110)>

Or

> 10.times.collect{|i| 100 + i}.each
#<Enumerator: [100, 101, 102, 103, 104, 105, 106, 107, 108, 109]:each>

Something like this would be nice:

100.next(10)

Answer 1

Maybe this could work:

(1..10).each.with_index(100) do |elem, i| puts "#{i}: #{elem}" end


100: 1
101: 2
102: 3
103: 4
104: 5
105: 6
106: 7
107: 8
108: 9
109: 10

Answer 2

(100..110).each

or more generic

(start..start+offset).each

Answer 3

How about a range:

[6] pry(main)> offset = 10  
=> 10  
[7] pry(main)> (100..(100 + offset)).collect { |i| i }   

=> [100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110]  
[8] pry(main)> (100..(100 + offset)).collect { |i| i }