質問

MATCH (hank)-[]->(hyperedge)-[]->(cletus)

If Hank has multiple relationships to hyperedge and/or hyperedge has multiple relationships to Cletus, but there is only one relationship from Hank through hyperedge to Cletus, will this query give me that relationship?

Assuming the answer to that is yes, if I do this:

CREATE (hank)-[:FOO]->(hyperedge)-[:BAR]->(cletus)

will

MATCH (hank)-[:FOO]->(hyperedge)-[:BAR]->(cletus)

give me the relationship I just created, if Hank has multiple FOO relationships to hyperedge and/or hyperedge has multiple BAR relationships to Cletus?

役に立ちましたか?

解決

It depends, if hank, hyperedge and cletus are fixed, then yes,

Otherwise you probably want to use:

MATCH shortestPath((hank)-[:FOO]->(hyperedge)-[:BAR]->(cletus))

to get only one.

Otherwise you have to "tag" that relationship somehow, e.g. with a property.

MATCH (hank)-[:FOO {tag:1}]->(hyperedge)-[:BAR  {tag:1}]->(cletus)
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