Remove all before and after Number X Number

Question

I ask my first question here because I need to isolate some characters in

Fri  2 Mar 2012  11:14:25
JPEG **960x640** 960x640+0+0 8-bit sRGB 64.7KB 0.016u 0:00.017

I want isolate 960X640 but this variable can change every time :( And the result I got is on many line like the example.

So I need a regex to delete all before 960X640 and all after.

Thank you so much if you try to help me :)

Answer 1

This regex should match the target:

[0-9]+x[0-9]+

So this should work to remove everything else:

Search: .*[0-9]+x[0-9]+.*
Replace (perl etc): \1 
Replace (java): $1

Answer 2

Sed would use syntax like:

s/^[^0-9]+[[:space:]]([0-9]+x[0-9]+)[[:space:]].*$/\1/

Perl would look like:

s/^\D+\s([0-9]+x[0-9]+)\s.*$/$1/

For example:

$ echo 'JPEG 960x640 960x640+0+0 8-bit sRGB 64.7KB 0.016u 0:00.017' | sed -r 's/^[^0-9]+[[:space:]]([0-9]+x[0-9]+)[[:space:]].*$/\1/'
960x640

Answer 3

This must solve your problem:

/\d+x\d+/