Replacing char with single quote using tr in shell scripting

Question

I want to replace new line char(\n) with ',' (along with starting and closing single quotes) in shell script by using tr command. But tr command is not replacing char correctly

Here is the command i used:

< 1.txt tr "\n" "','" 

Output for this command :

erer'erer.'erer'erer'

File 1.txt is like :

erer
erer.
erer
erer

Please suggest me how this can be done using the same command.

Question Edited

Answer 1

tr is not the right tool for this since tr does char by char translation instead of char to a string replacement. use awk:

awk '{printf("'"'"'%s'"'"',", $0)} END{print ""}' 1.txt

To avoid all weird double quote/single quote stuff use:

awk '{printf("\x27%s\x27,", $0)} END{print ""}' 1.txt

To avoid printing comma after last line:

awk '{a[cnt++]=$0} END{ for (i=0; i<length(a)-1; i++) printf("\x27%s\x27,", a[i]); 
      print a[i]}' 1.txt

Answer 2

tr is only to transliterate characters. You could do:

$ seq 10 | sed "s/.*/'&'/" | paste -sd, -
'1','2','3','4','5','6','7','8','9','10'

Or if you don't want the first and last ':

$ seq 10 | sed '$!G;$!G' | paste -sd "','" -
1','2','3','4','5','6','7','8','9','10