質問

I know configuring OSIVF is a common pain point. I've read all the pages I could find over that last couple of days, but nothing seems to get me past this issue. I have succeeded in getting myself confused, tho. I'm trying to keep this config really simple as the web app is pretty straightforward. Well, here's the error:

java.lang.IllegalStateException: No WebApplicationContext found: no ContextLoaderListener registered?
org.springframework.web.context.support.WebApplicationContextUtils.getRequiredWebApplicationContext(WebApplicationContextUtils.java:90)
org.springframework.orm.hibernate4.support.OpenSessionInViewFilter.lookupSessionFactory(OpenSessionInViewFilter.java:190)

Here's the web.xml:

<web-app version="2.4"
    xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Test MVC Application</display-name>

    <servlet>
        <servlet-name>onepic</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>onepic</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

    <filter>
        <filter-name>hibernateFilter</filter-name>
        <filter-class>org.springframework.orm.hibernate4.support.OpenSessionInViewFilter</filter-class>
        <init-param>
            <param-name>sessionFactoryBeanName</param-name>
            <param-value>sessionFactory</param-value>
        </init-param>
    </filter>

    <filter-mapping>
        <filter-name>hibernateFilter</filter-name>
        <url-pattern>/</url-pattern>
    </filter-mapping>



    <filter>
        <filter-name>CharacterEncodingFilter</filter-name>
        <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
        <init-param>
            <param-name>encoding</param-name>
            <param-value>UTF-8</param-value>
        </init-param>
        <init-param>
            <param-name>forceEncoding</param-name>
            <param-value>true</param-value>
        </init-param>
    </filter>
    <filter-mapping>
        <filter-name>CharacterEncodingFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>


</web-app>

Finally, here's some bits from onepic-servlet.xml:

<bean id="datasource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
    <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
    <property name="url" value="jdbc:mysql://localhost:3306/onePic?characterEncoding=UTF-8"/>
    <property name="username" value="onePic"/>
    <property name="password" value="onePic"/>
</bean>

<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="datasource" />
    <property name="packagesToScan" value="com.sandofamily.onePic"/>
    <property name="hibernateProperties">
        <props>
            <prop key="hibernate.dialect"> org.hibernate.dialect.H2Dialect</prop>
            <prop key="hibernate.show_sql">true</prop>
        </props>
    </property>
</bean>

<tx:annotation-driven/>

<bean id="transactionManager"
      class="org.springframework.orm.hibernate4.HibernateTransactionManager">
    <property name="sessionFactory" ref="sessionFactory"></property>
</bean>

Again, I'm so sorry for re-asking such a common problem, but I must be missing some bit of knowledge that ties this all together.

役に立ちましたか?

解決

You haven't configured your Context in your web.xml, so when Spring tries to find its Context you get this error.

This shows how to configure Spring using a xml file, but you can also do this using a Java configuration based. You can find something here.

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