Map from 2 different nodes to duplicated target node

Question

I have this source and target :

I need that my map would produce a target with 2 nodes of "T".

The first one is with "A" source content, and the second is with "B" source content.

For example:

Input:

<Root>
 <A>
   <FieldA>FA</FieldA>
   <FieldB>FB</FieldB>
 </A>
 <B>
   <FieldC>FC</FieldC>
   <FieldD>FD</FieldD>
 </B>
</Root>

Requested Output:

<Root>
    <T>
      <F1>FA</F1>
      <F2>FB</F1>
    </T>
    <T>
      <F1>FC</F1>
      <F2>FD</F2>
    </T>   
</Root>

*** There is also a condition regarding the map from "B" to "T"

Answer 1

Place looping functoid

A --> Looping Functoid --> T
B --> Looping Functoid --> T

FieldA --> F1
FieldB --> F2
FieldC --> F1
FieldD --> F2

Answer 2

The following does what you want to achieve:

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">

<xsl:output method="xml" indent="yes"/>

 <xsl:template match="/">
  <xsl:apply-templates/>
 </xsl:template>

 <xsl:template match="Root">
  <xsl:copy>
   <xsl:apply-templates/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="A|B">
  <xsl:element name="T">
    <xsl:apply-templates/>
  </xsl:element>
 </xsl:template>

 <xsl:template match="*[parent::A or parent::B]">
  <xsl:choose>
     <xsl:when test="./name() = 'FieldA' or ./name() = 'FieldC'">
        <xsl:element name="F1">
           <xsl:value-of select="."/>
        </xsl:element>
     </xsl:when>
     <xsl:otherwise>
        <xsl:element name="F2">
           <xsl:value-of select="."/>
        </xsl:element>
     </xsl:otherwise>
  </xsl:choose>
 </xsl:template>

</xsl:stylesheet>

Besides, please take the time to report on what you have tried so far. SO is not there to do your homework. So, show your effort in your future questions.

Answer 3

Just link A and B to T through a Looping Functoid.