These are part of the previous line's operands. The "immediate" (constant) numbers are encoded as 32-bits. So 0x07 takes up 4 bytes: 07 00 00 00
. Whatever you're using to disable is showing you the last byte on a different line.
Why there are some "meaningless" memory slot in the disassembly code?
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20-09-2022 - |
문제
I use objdump to disassemble some ELF file on 32 bit Linux.
The asm file are in Intel format.
In the disassemble file, I notice some memory slot like below:
80483ed: c7 44 24 18 07 00 00 mov DWORD PTR [esp+0x18],0x7
80483f4: 00
80483f5: c7 44 24 1c 0c 00 00 mov DWORD PTR [esp+0x1c],0xc
80483fc: 00
80483fd: c7 44 24 20 01 00 00 mov DWORD PTR [esp+0x20],0x1
8048404: 00
8048405: c7 44 24 24 fe ff ff mov DWORD PTR [esp+0x24],0xfffffffe
804840c: ff
and the original assemble file is :
mov DWORD PTR [esp+24], 7
mov DWORD PTR [esp+28], 12
mov DWORD PTR [esp+32], 1
mov DWORD PTR [esp+36], -2
Could anyone tell me what does the memory address like "80483f4","80483fc" do?
Is this issue related to the memory alignment?
Thank you!
해결책
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