In Firebug's HTML view, is there a way to inspect the underlying Dijit object of a widget's DOM node?

StackOverflow https://stackoverflow.com/questions/20977499

  •  25-09-2022
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문제

That is, by selecting an HTML element that would be a Dijit's containerNode, being able to inspect that Dijit's properties. Sort of a poor man's substitute for the old DojoFireBugExtension's widget view.

Or, assuming there's no appropriate break point, a work-around?

도움이 되었습니까?

해결책

I usually copy the ID (generated or selfmade) and paste the following in my console:

dijit.byId("my_id");
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