문제

Been looking for the simplest way to capture argv[4] and any more after that?

$ node script.js foo bar la di da

var a = process.argv[2];
var b = process.argv[3];
var c = process.argv[?];

wanting to capture la di da .. was thinking >= or similar..? maybe forEach?

도움이 되었습니까?

해결책

If you mean that you want to capture the remaining arguments into a single variable, then try:

var c = process.argv.slice(4);

c will be a variable containing the remaining CLI parameters

라이센스 : CC-BY-SA ~와 함께 속성
제휴하지 않습니다 StackOverflow
scroll top