XSD - define type with parameter

https://stackoverflow.com/questions/22090814

18-10-2022
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문제

Is it possible to define parameter for a type ? I want to have type that represents fixed length string but I dont want do define multiple such types for different lengths, that is TFixedString(N) so I could use TFixedString(2) and TFixedString(16).

해결책

No you can not do this. It is not supported in XSD.

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