How to execute a funtion after a time delay in php?

Question

I have created a button called "Generate" , when click event is performed it should start a timer after reaching 60 sec it should perform an if statement. I tried the following code but its not working.

if(isset($_POST['generate']))
      {
       $timer = time();
        if($timer = $timer+5)
       {
         $query = mysql_query("UPDATE user_login SET password='' WHERE username = 'ajai sandy'") ;
                     $qry_run = mysql_query($query);
       }

In the above code I have used the system time , I could use both the system time or a timer to complete this action.

Answer 1

if(isset($_POST['generate']))
      {
      sleep(60);
      // AND NOW action;
      }

But rather use JS...

Answer 2

You shouldn't do this on server side! But you could do it with PHP's sleep() method.

Answer 3

Do you want, that 'if' performs after 60 seconds? Then you need to use sleep()

if(isset($_POST['generate']))
  {
   sleep(60);
   if(condition)
   {
    // todo
   }

Answer 4

You need to just first check the current time then after you need to use sleep

if(isset($_POST['generate']))
      {
       $timer = time();
     sleep(5)

        //your condition

or you can just use this with client side scripting lanugage as well there is a function setTimeout

window.setTimeout(FUNCTION_NAME,60);