Django SQL Loop Through Menu & Sub-menu

Question

Trying to create a menu with "City/Location" having sub-menu for "Neighborhoods"

• New York
• -- Neighborhood
• -- Neighborhood
• -- Neighborhood
• Chicago
• -- Neighborhood
• -- Neighborhood
• -- Neighborhood
• Miami
• -- Neighborhood
• -- Neighborhood
• -- Neighborhood

View.py

def location(request):
args['getlocs'] = Location.objects.filter(switch=1, restaurants__city_id=8).order_by('name')
args['gethoods'] = Hood.objects.filter(switch=1, restaurants__city_id=8).distinct().order_by('name')
return render_to_response('location.html', args)

Template.html

<ul>
   {% for location in getlocs %}
      <li>{{ location.name }}</li>
        <ul>
           {% for hood in gethoods %}
              <li>{{ hood.name }}</li>
           {% endfor %}
        </ul>
    {% endfor %}
</ul>

Obviously when I run this, every neighborhood in db is displayed and I only need neighborhood that belongs in each city/location to be displayed. Is there a way just to add some condition to the html template or do I need to change the view? Thanks much!

EDIT:

class Location(models.Model):
name = models.CharField(max_length=50, db_column='location', blank=False, null=False)
city = models.ForeignKey('City', related_name="locations")
...

class Hood(models.Model):
name = models.CharField(max_length=50, db_column='hood')
city = models.ForeignKey('City', related_name='hoods')
location = models.ForeignKey('Location', related_name='hoods')
... 

class Restaurant(models.Model):
name = models.CharField(max_length=50, db_column='name', blank=True)
location = models.ForeignKey('Location', related_name="restaurants")
hood = models.ForeignKey('Hood', null=True, blank=True, related_name="restaurants")
...

Answer 1

If I am under standing the relationship correctly, a City has many Neighborhoods. So this is a many-to-many relationship. In the models.py this would look like

from django.db import models

class Neighborhood(models.Model):
  name = models.CharField(max_length=100)

class City(models.Model):
  name = models.CharField(max_length=100)
  neighborhoods = models.ManyToManyField(Neighborhood)

You can then set up your page to accept the city name as an argument in the href, and then call a page view for only neighborhoods in that city. Your href link in the template to go to the city view with only it's neighborhoods may look like this:

<a href="{% url 'city_view' city.name %}">Link</a>

That is linked to this url in your urls.py:

url(r'city/(?P<city_name>.+)/$', views.city_view, name='city_view')

Then your view in views.py that will filter for only neighborhoods in that city may look like this:

def city_view(request, name):
  city = City.objects.get(name=name)
  neighborhoods = city.neighborhoods.all()
  return render(request, 'template.html', {'neighborhoods': neighborhoods})

Then call only the neighborhoods for that city in the template.html:

{% for neighborhood in neighborhoods %}
  neighborhood.name
{% endfor %}

This should hopefully show the database calls, views.py progression, and how it routes the view based on what is requested in the urls.py. If you need anything else, lmk.