문제

I have two questions.

  1. Does the rigid transformation represented in Eigen::Affine3f and Eigen::Matrix4f will be the same ?

  2. How can we convert from Eigen::Affine3f to Eigen::Matrix4f and vice versa ?

Thanks for your help!

도움이 되었습니까?

해결책

Yes, internally an Affine3f stores a MatrixXf, so you can do:

Eigen::Affine3f A;
Eigen::Matrix4f M;
M = A.matrix();
A = M;               // assume that M.row(3) == [0 0 0 1]
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